![]() ![]() TypeError: 'in ' requires string as left operand, not NoneTypeįull error for the if statement: print(parser(lista_aziende_raw))įile "/home/enrico/Documents/Learning_Python/edo/web_scraper. pattern and update with another column - Stack Overflow Search strings in. The full error for the list comprehension: File "/home/enrico/Documents/Learning_Python/edo/web_scraper.py", line 41, in Using this to filter the DataFrame will look like this: pandas. ![]() lista_aziende_raw = ĮDIT: Here the output of print(lista_aziende_raw). I also tried to put it in an if statement, following this answer but that spits out TypeError: argument of type 'NoneType' is not iterable'. Lista_aziende_raw.append(link.get('href')) Is there a way to get what I want using list comprehension, or should I just use the re module? lista_aziende_raw = As such, passing more than 5 tags will always return zero results. I made them into generator comprehensions, so they are more memory efficient on their own (even though here I cast them to lists, as soon as I want to use them). mylist 'foo','bar','baz','>','5.2' With onlywords token for token in mylist if token.isalpha() Without onlywords filter(str.isalpha, mylist) Personally I don't think you have to use a list comprehension for everything in Python, but I always get frowny-faced when I suggest map or filter answers. This is an and constraint, passing taggedc java will return only those questions with both tags. I would make this two different functions, one for filtering all names of length n and one for all names starting with some letter. I guess that in only looks for identical results, hence no results. To constrain questions returned to those with a set of tags, use the tagged parameter with a semi-colon delimited list of tags. I know for a fact that names that contain Azienda are present in the list, but I get an empty list. I'm a beginner, I want to filter the list lista_aziende_raw. ![]()
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